## Kotlin Program:

- To swap 2 numbers using XOR operator

#### Example:

User Input
1st number: 3
2nd number: 5

After Swap, Output:
1st number : 5
2nd number : 3

``````import java.util.Scanner
fun main(args: Array<String>) {

print("Enter 1st number : ")
val userInput = Scanner(System.`in`)
var n1:Int = userInput.nextInt()
print("Enter 2nd number : ")
var n2:Int =userInput.nextInt()

n1 = n1 xor n2
n2 = n2 xor n1
n1 = n1 xor n2
print("After Swapping\n Value of 1st number : \$n1 \n Value of 2nd number : \$n2")
}``````

### Output:

```  Enter 1st number : 7
Enter 2nd number : 15
After Swapping
Value of 1st number : 15
Value of 2nd number : 7
```
Program
puzzle

We are using binary XOR operator (^)

``````//Lets take n1=7, n2=3
n1 = n1 xor n2 //Here n1=4, n2=3
n2 = n2 xor n1 //Here n1=4, n2=7
n1 = n1 xor n2 //Finally n1=3, n2=7``````
```Remember :
A B (A xor B)
0 0    0
0 1    1
1 0    1
1 1    0```
Concept

Coming Soon !

Quick
Tutorial

# Quote

Give a man a fish and you feed him for a day; teach a man to fish and you feed him a lifetime.