## Java Program:

- To check number is in binary or not

#### Example:

User Input: 11111

Output: Number is in binary form

``````import java.util.Scanner;
public class CheckBinary {
public static boolean binary(long num) {
while(num!=0) {
if(num%10==0 || num%10==1)
num/=10;
else return false;
}
return true;
}

public static void main(String []args) {
long num;
Scanner userInput = new Scanner(System.in);
num = userInput.nextLong();

if(binary(num))
System.out.println("Number is in binary form");
else
System.out.println("Number is not in binary form");
}
}``````

### Output:

```  Enter Your number : 1101
Number is in binary form
```
Program
number

Binary Numbers : Numbers with only 0 & 1 combination

`Examples like: 101, 111, 10, 11111`

Main Logic :

``````public static int binary(long num) {
while(num!=0) {
if(num%10==0 || num%10==1)
num/=10;
else return false;
}
return true;
}``````

Divide the number by 10 while your number becomes 0[ZERO] &
In-between check, is there any remainder other than 0 & 1

Concept

Coming Soon !

Quick
Tutorial

# Quote

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