- To swap 2 numbers using XOR operator
User Input
1st number: 3
2nd number: 5
After Swap, Output:
1st number : 5
2nd number : 3
#include <iostream>
using namespace std;
int main() {
int n1,n2;
cout<<"Enter 1st number: ";
cin>>n1;
cout<<"Enter 2nd number: ";
cin>>n2;
n1^=n2;
n2^=n1;
n1^=n2;
cout<<"After Swap"<<endl;
cout<<"1st number :"<<n1<<"\n2nd number :"<<n2;
return 0;
}
Enter 1st number : 7 Enter 2nd number : 15 After Swap 1st number : 15 2nd number : 7Program
We are using binary XOR operator (^)
//Lets take n1=7, n2=3
n1^=n2; //Here n1=4, n2=3
n2^=n1; //Here n1=4, n2=7
n1^=n2; //Finally n1=3, n2=7
Remember : A B A^B 0 0 0 0 1 1 1 0 1 1 1 0Concept