## C++ Program:

- To check number is in binary or not

#### Example:

User Input: 11111

Output: Number is in binary form

``````#include <iostream>
using namespace std;

int binary(long long num) {
while(num!=0){
if(num%10==0 || num%10==1)
num/=10;
else return 0;
}
return 1;
}

int main() {
long long num;
cin>>num;
if(binary(num))cout<<"Number is in binary form";
else cout<<"Number is not in binary form";
return 0;
}``````

### Output:

```  Enter Your number : 1101
Number is in binary form
```
Program
number

Binary Numbers : Numbers with only 0 & 1 combination

`Examples like: 101, 111, 10, 11111`

Main Logic :

``````int binary(int num) {
while(num!=0){
if(num%10==0 || num%10==1)
num/=10;
else return 0;
}
return 1;
}``````

Divide the number by 10 while your number becomes 0[ZERO] &
In-between check, is there any remainder other than 0 & 1

Concept

Coming Soon !

Quick
Tutorial

# Quote

Give a man a fish and you feed him for a day; teach a man to fish and you feed him a lifetime.